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6x^2-60x+150=6
We move all terms to the left:
6x^2-60x+150-(6)=0
We add all the numbers together, and all the variables
6x^2-60x+144=0
a = 6; b = -60; c = +144;
Δ = b2-4ac
Δ = -602-4·6·144
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12}{2*6}=\frac{48}{12} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12}{2*6}=\frac{72}{12} =6 $
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